2x^2-2x+x^2-3x-2x^2=20

Solution for 2x^2-2x+x^2-3x-2x^2=20 equation:

2x^2-2x+x^2-3x-2x^2=20

We move all terms to the left:

2x^2-2x+x^2-3x-2x^2-(20)=0

We add all the numbers together, and all the variables

x^2-5x-20=0

a = 1; b = -5; c = -20;
Δ = b2-4ac
Δ = -52-4·1·(-20)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{105}}{2*1}=\frac{5-\sqrt{105}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{105}}{2*1}=\frac{5+\sqrt{105}}{2}
$